Lil math puzzle

[DoesntMatter]

Well mercury (II) has a hard-on for sulfuric compounds of higher substitutions so I guess someone decided to take advantage of this

[Only-virgins]

Its for when you are describing sequences & series, OV. Its usually covered in first year calc as you start to learn about limits & convergence tests & that sort of thing.

Yea I know, we still used X and Y.

[DoesntMatter]

x, y, z, beta, alpha, gamma it doesn't matter

[bohemiandonut]

And yet none of you nerds can handle the REAL real science behind it all? I may have been drunk when I wrote that s but it will still trip you the f out, b.

~~~~~S = k log W~~~~~

[DoesntMatter]

Donut,

I (r = 1 - sinθ) U


Now rub my nipples until I lactate asshole

[DoesntMatter]

BTW I'm just messing around with you donut

[DoesntMatter]

Here is another little math puzzle that is nice because it only requires up to middle school math knowledge

?

[IndiReloaded]

DM, did you ever get the blog about the guy pissed at Verizon b/c they didn't understand the difference b/t 0.002 cents/kilobyte and 0.002 dollars? It was going around a couple years ago. Eventually he got so frustrated he wrote them a cheque for .002 dollars plus e^(i*pi) + the sum of 1/(2^n)--how do you make the Sigma?? If not, I'll try to find it for you. I've been dying to do this to my bank but they haven't given me reason yet.

[IndiReloaded]

Here it is, I wanted it for my photo collection anyway:

[DoesntMatter]

lol no I do not remember that

[DoesntMatter]

Anybody...

[IndiReloaded]

Sorry, DM, no bites? I didn't want to jump straight in. Here's the best I've come up with:

Its a repeating infinite expression, right? So we can substitute in 'x' for the 1+(1/1+1/1+1/, etc.) on both sides of the equation. I think you get something like

x=1+1/x, where x is that repeating expression. You'll end up with some kind of polynomial that you can solve with something like the quadratic formula (maybe)?

i.e. x^2=x+1 or x^2-x-1=0, then solve for x? There should be two answers but I guess only one will make sense. Is this roughly right? I don't remember how to derive the quadratic formula anymore DM (I could in a pinch, I guess) but its been a looong time.

I think word problems of the sort you first posted are more fun for ppl in general. Just a guess.

[DoesntMatter]

I think word problems of the sort you first posted are more fun for ppl in general. Just a guess.

Maybe, but also people are probably run down from college and therefore don't want to do anymore problems (like me!)

But you are very right with the equation you established, x = 1 + 1/x because the infinite series appears twice

So when you set all that shit equal to 0 you can solve for the roots of the quadratic, and obviously disregard the negative because it is meaningless. The number you get is (1 + √5)/2, also known as the Golden Ratio which apparently is an important number in art

[IndiReloaded]

The number you get is (1 + √5)/2, also known as the Golden Ratio which apparently is an important number in art

Oooh. Is that like the Sacred Golden Balls?

[IndiReloaded]

Okay, you don't need any math for this one:

"Is the set of all sets that are not members of themselves a member of itself?"

That's the problem, as written. No tricks, no hints. Good luck.